step by step resolutions
1) n+n+1+n+2=51
3n+3=51
3n=48
n=16
the three numbers are 16, 17 and 18.
2) x+15=4x
3x=15
x=5
radha is now 5 years old
3) the two digits are x and y.
y=3x
(10x+y)+(10y+x)=88
y=3x
11x+11y=88
y=3x
x+y=8
x+3x=8
x=2
the original number can be either 28 or 82.
4) n+(n+2)+(n+4)=48
3n+6=48
3n=42
n=14
the numbers are 14, 16 and 18.
5) y=x+3
10y+x+10x+y=143
y=x+3
11x+11y=143
y=x+3
x+y=13
x+x+3=13
2x=10
x=5
the original number can be 57 or 75.
hope this !