I need help with numbers 2,3,4,5,6 I need to graduate so help

2.

sinα=√3/(2√7)

cosα=5/(2√7)

tanα=5/√3

cscα=(2√7)/√3

secα=(2√7)/5

*note* you can simplify the above further (by rationalizing them), but I think it's probably fine to leave them as is *

3.) g15.9

4.)25.4

5.) 70.8

6.) 36.4

Step-by-step explanation:

Cot is the inverse of toa so cot= adj/opp

This means the traingle's adjacent side is √3 and its opposite is 5

with this information let's figure out the hypotonouse

√3²+5²=c²

3+25=c²

28=c²

√28=c

√28=2√7

which means the triangle's

opposite= √3

hypotonous= 2√7

Adjacent= 5

With all of this we can just plug in the numbers to find the missing information (where α=angle or theta)

sinα=√3/(2√7)

cosα=5/(2√7)

tanα=5/√3

cscα=(2√7)/√3

secα=(2√7)/5

For this one we have the adjacent and need the opposite

we will use TOA

Tan(25)=x/34

34tan(25)=x

x=15.9

4.) For this one we have the adjacent but need the hypotonouse

we will use CAH

cos(48)=17/x

17/cos(48)=x

x=25.4

5.) for number 5 we have the oppsite and hypotonouse and so we'll use SOH

sin(α)=17/18

α=70.8

6.) For this one we have the opposite and adjacent and so we'll use TOA

Tan(α)=(31/42)

α=36.4

the answers c

,xzgv

step-by-step explanation:

; oqirjg'