Mathematics, 14.05.2021 04:50 shmueller1554

Kilgore's Deli is a small delicatessen located near a major university. Kilgore does a large walk-in carry-out lunch business. The deli offers three luncheon chili specials, Wimpy, Dial 911, Fire Bowl. At the beginning of the day, Kilgore needs to decide how much of each special to make (he always sells out of whatever he makes). The profit on one serving of Wimpy is $0.6, on one serving of Dial 911 is $0.55, and on one serving of Fire Bowl is $0.65.
The following table shows the required ingredients to make one serving of each chili special, and the available amount of each ingredient for today :
Ingredient Required ingredient for each serving of Wimpy Required ingredient for each serving of Dial 911 Required ingredient for each serving of Fire Bowl Available Amount
Beef (lbs) 1 1 1.5 15
Onions (cup) 2 2 2 20
Special Sauce (oz) 5 2 3 90
Hot Sauce (oz) 0 5 6 60
Based on the historical sales data, Kilgore's Deli has the following considerations:
the number of servings for Fire Bowl must be at least 10% of the total number of servings for all three luncheon chili specials.
the number of servings for Fire Bowl, however, cannot exceed the number of Dial 911 by more than 3.
the available number of servings for Dial 911 must be at least 2.
(1.1) Develop the linear programming model to help determine the number of servings of Wimpy, Dial 911, and Fire Bowl to make in order to maximize his profit today. Type your algebraic formulation in the specified area in Q1 tab of the Excel template. Note you will not get full credits without including the algebraic formulation.
(1.2) Solve your LP model in Excel and fill in the following blanks (show your work in Q1 tab):
The optimal number of servings of Wimpy is
The optimal number of servings of Dial 911 is
The optimal number of servings of Fire Bowl is
The maximum possible profit is
Is there any leftover of ingredients as a result of this optimal solution? if yes, enter the amount. Otherwise, just type 0.
Amount of beef leftover
Amount of onion leftover
Amount of special sauce leftover
Amount of hot sauce leftover

Answers: 2

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Answers

Answer from: sarahidan

z (max) = 6.15

x₁ = 1 x₂ = 3 x₃ = 6

Amount of beef leftover 2 lb

Amount of onions leftover 0

Amount of Special Sauce leftover 61

Amount of Hot Sauce leftover 9

Step-by-step explanation:

Ingredients Beef Onions Special S Hot S Profit

Wimpy (x₁) 1 2 5 0 0.6

Dial 911 (x₂) 1 2 2 5 0.55

Fire Bowl (x₃) 1.5 2 3 6 0.65

Available 15 20 90 60

Objective Function z:

z = 0.6*x₁ + 0.55*x₂ + 0.65*x₃ to maximize

Subject to:

1) Quantity of beef : 15

x₁ + x₂ + 1.5*x₃ ≤ 15

2) Quantity of onions: 20

2*x₁ + 2*x₂ + 2*x₃ ≤ 20

3) Quantity of Special sauce: 90

5*x₁ + 2*x₂ + 3*x₃ ≤ 90

4) Quantity of hot sauce: 60

0*x₁ + 5*x₂ + 6*x₃ ≤ 60

5) Condition: The number of servings for Fire Bowl must be at least 10% of the total number of servings for all three luncheon chili specials.

x₃ ≥ 0.1 ( x₁ + x₂ + x₃ ) or x₃ ≥ 0.1*x₁ + 0.1 *x₂ + 0.1*x₃

x₃ - 0.1*x₁ - 0.1 *x₂ - 0.1*x₃ ≥ 0

- 0.1*x₁ - 0.1 *x₂ + 0.9 *x₃ ≥ 0

6)Condition: The number of servings for Fire Bowl, however, cannot exceed the number of Dial 911 by more than 3.

x₃ - x₂ ≤ 3

7)the available number of servings for Dial 911 must be at least 2.

x₂ ≥ 2

General constraints:

x₁ ≥ 0 x₃ ≥ 0 all integers

With on-line solver solution is:

z (max) = 6.15

x₁ = 1 x₂ = 3 x₃ = 6

By sbstitution on the constraints

1) x₁ + x₂ + 1.5*x₃ ≤ 15 1 + 3 + 9 = 13

Amount of beef leftover 2 lb

2) 2*x₁ + 2*x₂ + 2*x₃ ≤ 20 2 + 6 + 12 = 20

Amount of onions leftover 0

3) 5*x₁ + 2*x₂ + 3*x₃ ≤ 90 5 + 6 + 18 = 29

Amount of Special Sauce leftover 61

4)0*x₁ + 5*x₂ + 6*x₃ ≤ 60 15 + 36 = 51

Amount of Hot Sauce leftover 9

Answer from: Quest

nkcoicjc

Answer from: Quest

⊂⊃⊂⊃ω $\frac{x}{y}\left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right] \left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right] \\ x^{2} \pi \pi \left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right] \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx x_{123} \left \{ {{y=2} \atop {x=2}} \right. \sqrt[n]{x} x_{123}$

step-by-step explanation:

i hope this : )

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