Can someone help me asap please? Math question, Pre algebra.

Here we have the table:

To complete the table, we just need to input the different values of t in the equation:

f(t) = 16*t^2

Then for the first value, t = 20, we get:

f(20) = 16*(20)^2 = 6,400

now we write that in the table:

Now we just need to do the same for the other 3 values:

f(21) = 16*(21)^2 = 7,056

f(22) = 16*(22)^2 = 7,744

f(23) = 16*(23)^2 = 8,464

Then the completed table is:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

your answer is  

a.

5

step-by-step explanation: