List the first 9 terms of the sequence defined recursively by Sn = Sn-2. (Sn-1 - 1), with S1 = 2 and S2 = 3

Explanation

Given that Sn = Sn-2 . (Sn-1 - 1)

Tn = Sn - Sn-1

Tn = Sn-2 . (Sn-1 - 1) - (Sn-3 . (Sn-2 - 1))

T3 = S1.(S2-1) - (S0.(S1-1)

T3 = 2.(3-1) - 1.(2-1)

T3 = 2(2) - 1(1)

T3 = 4-2

T3 = 3

T4 = S2.(S3-1) - (S1.(S2-1)

T4 =3.(-1) - 1.(2-1)

T4 = 2(2) - 1(1)

T4 = 4-2

T4 = 3

the answer is 24

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~