write down the coordinates of a point which lies in the second quadrant and 6 units far from both the axes​

Can someone answer this question for me

If x-1 and x+3 are the factors of x3+10x2+ax+b find a and b

36x2 + 49y2 = 1,764 the foci are located at: a) (-√13, 0) and (√13,0) b) (0, -√13) and (0,√13) c) (-1, 0) and (1, 0)