Bowl A has 3 red chips and 5 blue chips. Bowl B has 5 red chips and 4 blue chips. A chip is chosen at random from Bowl A and placed in Bowl B. Then a
chip is chosen at random from Bowl B.
2.2.1 Write down the sample space of this experiment.
[2]
[3]
2.2.1 Compute the probability that the second chip chosen is Red.
2.2.2 Given that the second chip chosen was red, what is the probability that
the first chosen chip was red?
[2]
2.2.3 Given that the second chip chosen was blue, what is the probability
that the first chosen chip was blue?
[2]

because 1.2 isnt half of 6 duh

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it