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5.) 12 over 7.

Extra credit: x = 5 outside the sqrt 2, or x= -5 outside the sqrt 2.

Step-by-step explanation:

You apply radical rule: n sqrt a/b = nsqrt a over n sqrt b, assuming a equals > or equal to 0, and b the same thing. which gives you sqrt 144 over sqrt 49. So the sqrt of 49 =7 which is the denominator. so now this gives you sqrt 144 over 7. Then do the same thing with the sqrt 144. So the sqrt of 144 =12. So now the problem is 12 over 7 is simplified.

Extra Credit explanation:

6x^2+10=310. First thing we want to do is get the 6x^2 by itself. To do this we are going to subtract 10 from the 310. So it should look like 310-10. you should get 300. So now the equation looks like 6x^2=300. Now, you are going to divide the 6x^2 by 6 and 300 by 6. you get x^2=50. for x^2 = f(a) the solutions are x= sqrt f(a), -sqrt f(a). Doing this we get x= sqrt 50 and x = -sqrt 50. Sqrt 50 is 5 sqrt 2. -Sqrt 50 is -5 sqrt 2. so the answers are x=5sqrt 2 and x=-5 sqrt 2

the answer is c

hope this !