Give the trigonometric form of each vector (leave the magnitude as a square root) p= (<2V6, -2V2)

or

Step-by-step explanation:

Find the magnitude of :

Find the direction angle of :

Since is our reference angle, we determine our direction angle by verifying our angle is in Quadrant IV, which is where the vector is located. Therefore,

To represent a vector's magnitude and direction in trigonometric form, we use the form or .

In conclusion, the trigonometric form of the vector is:

or

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.