Can someone please help question: An airplane is flying at an elevation of 1500 feet. What is the airplane's angle of elevation from the runway when it is 5000 feet from the runway?

Angle of elevation of the airplane = 17.46 degrees

Step-by-step explanation:

From the picture attached,

An airplane is flying at an altitude of 1500 ft at point A.

Runway starts from point B from which distance of the airplane is 5000 ft.

Now we apply sine rule in the given triangle ABC to measure the angle θ.

sinθ =

sinθ =

       =

degrees

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step-by-step explanation: