Find the sum of the 1st 100 terms: 100+98+96+
50
100
-98
1000

100

Step-by-step explanation:

Given :

Terms ( n ) = 100

First term ( a ) = 100

Series = > 100 + 98 + 96

Common difference ( d ) = 98 - 100 = > - 2

We know sum formula:

S_n = ( n / 2 ) ( 2 a + ( n - 1 ) d )

= > S_100 = ( 100 / 2 ) ( 200 + ( 100 - 1 ) - 2 )

= > S_100 = 50 ( 200 - 198 )

= > S_100 = 50 ( 2 )

= > S_100 = 100

Therefore, sum of first 100 terms is 100.

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.