area of a circle is increasing at a constant rate of 7.2 meters per second . What is the rate of increase in the radils of the circle at the instant when the circumference of the circle is 20pi meters

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step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

answer: sherk

step-by-step explanation:

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