I don't know how to do this please help explain how to do it aswell as give the answer so i understand

We are given:

The function: y = -16t² + 64

where y is the height from ground, t seconds after falling

Part A:

when the droplet would hit the ground, it's height from the ground will be 0

replacing that in the given function:

0 = -16t² + 64

16t² = 64                          [adding 16t² on both sides]

t² = 4                                [dividing both sides by 16]

t = 2 seconds                  [taking square root of both sides]

Part B:

for second droplet,

height from ground = 16 feet

time taken = t seconds

acceleration due to gravity = 10 m/s²

initial velocity = 0 m/s

h = ut + (1/2)at²                 [second equation of motion]

16 = (0)(t) + (1/2)(10)(t²)

16 = 5t²

t² = 16/5

t = 1.8 seconds (approx)

Therefore, the second droplet takes the least amount time to hit the ground

idk

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