Please help
Find f(-4) for f(x) = 9(3)^x.
A.1/3
B.1/9
C. -729
D. -108

D

Step-by-step explanation:

Using the law of radicals/ exponents

\sqrt{a^{3} }

a

3

⇔ a^{\frac{3}{2} }a

2

3

Consider the right side

\sqrt{729}

729

= \sqrt{9^{3} }

9

3

= 9^{\frac{3}{2} }9

2

3

Thus

9^{x}9

x

= 9^{\frac{3}{2} }9

2

3

Since the bases on both sides are equal, equate the exponents, so

x = \frac{3}{2}

2

3

→ D

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

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