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Total area of the fabric = 66 in.²

Step-by-step explanation:

The diagram of the stretched fabric shown takes the shape of a kite having two diagonals that intersect each other.

Total area of the fabric = area of the kite = ½(product of the two diagonals)

= ½(AC × BD)

We need to find AC and BD

BE = DE = 6 in. (Equal lengths)

BD = BE + DE

BD = 6 + 6 = 12 in.

AC = AE + CE

Apply Pythagorean theorem to find AE and CE

✔️AE = √(AB² - BE²) = √((√45)² - 6²) = √(45 - 36) = √9 = 3 in.

✔️CE = √(CD² - DE²) = √(10² - 6²) = √(100 - 36) = √64 = 8 in.

FIND AC:

✔️AC = AE + CE

AC = 3 + 8

AC = 11 in.

FIND the total area of the fabric:

✔️Total area = ½(AC × BD) = ½(11 × 12)

= ½(132)

= 66 in.²

hi,

3. 12.15, you are correct.

4.2.01, your first digit is correct,

hope this !

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: