A circular hot spring has a diameter of 110 meters. Overtime the hot spring decreases by 3 meters. By how many square meters does the area of the hot spring decrease?

511.04m^2

Step-by-step explanation:

A circular hot spring has diameter of 110 meters. Over time, the diameter of the spring decreases by 3 meters. By how many square meters does the area of the hot spring decrease

Area of a circle = πr²

Where : = π = pi = 3.14

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

3.14 x (110/2)² = 9498.5

Diameter after decrease = 110 - 3 = 107

3.14 x (107/2)² = 8987.5

Decrease in area = 9498.5 - 8987.5 = 511.03

55

52

9498.5

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.