A person invested $230 in an account growing at a rate allowing the money to double every 7 years. How long, to the nearest tenth of a year would it take for the value of the account to reach $3902

Step-by-step explanation:

A person invested $230 in an account growing at a rate allowing the money to double every 7 years. How long, to the nearest tenth of a year would it take for the value of the account to reach $3902

The formula is given as

A(t) =Ao (2)^t/k

Where

A(t) = 3902

Ao = 230

t = ?

k = 7 years

Hence,

3902 = 230 × (2)^t/7

We divide both sides by 230

3902/230 = 230 × (2)^t/7/230

16.965217391 = (2)^t/7

Find the ln of both sides

ln 16.965217391 = ln (2)^t/7

ln 16.965217391 = t/7 ln (2)

In 16.965217391/ln 2 = t/7

idk man good luck man

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.