Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter o...

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Step-by-step explanation:

Question is incomplete. Here's the whole question:

"Two solutions of different concentrations of acid are mixed creating 40 ml of a solution that is 32% acid. one-quarter of the solution is made up of a 20% acid solution. the remaining three-quarters is made up of a solution of unknown concentration, c. equation can be used to determine c, the unknown concentration?

a) 30c + 10(0.2) = 40(0.32)

b) (c) + (0.2) = 40(0.32)

c) (c)( (0.2)) = 40(0.32)

d) 30(c)(10(0.2)) = 40(0.32)"

With this, we can now solve the question.

We have a solution that was made mixing2 different solutions of acid. In this case, we can assume the following:

Solution 1 = 40 mL 32% acid

Solution 2 = 1/4 solution 1, 20% acid

Solution 3 = 3/4 solution 1, c% acid.

Thus we can say:

Solution 1 = Solution 2 + Solution 3     (1)

Now, 1/4 of the volume of solution 1, means that we use 10 mL of a 20%acid, and the remaining 30 mL is the unknown acid.

With this, we can discart option b) and c) because these option are not considering the volume of solution 3 used. Option d is not doing any sum, only multiplications, so, this is not the option to use. We can easily say it's option a, but let's prove it.

In general terms, concentrations and volume are related, and if we have two solutions, the information of these two solutions must be conserved in the resulting solution. In other words:

M₁V₁ = M₂V₂

According to this, the concentration of the unknown acid would be:

30c + 0.2*10 = 40(0.32)

30c + 2 = 12.8

30c = 10.8

c = 0.36

Which means that the concentration of the acid is 36%

Hope this helps

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step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.