Find the probability of having 2,3, or 4 successes in five trials of a binomial
experiment in which the probability of
success is 40%.
Round to the nearest tenth of a
percent.

65.3%

Step-by-step explanation:

P(2,3, OR 4)

You have to do each one individually then add them together

5C2(.4)^2 times (.6)^3 + 5C3(.4)^3 times (.6)^3 + 5C4(.4)^4 times (.6)^1=

.3465+.2304+.0768=.6528=65.3%

3,000,540

step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5