Consider the equation: 3+2 = 22 +30
1) Rewrite the equation by completing the square.
Your equation should look like (x + c)2 = d or (x – c)2 = d.

2) What are the solutions to the equation?
Choose 1
A
x = 1+2
B
x = -1/2
C = 12
D
2 = -1+2

3+2 = 22 +30=  59 1/2

(x + c)2 = d or (x – c)2 = d. = (c * d)(x) = 4x^3 + 18x^2 - 10x

X=1+2

Step-by-step explanation:

sorry if wrong was every confused

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source