Given P(A)=0.8P(A)=0.8, P(B)=0.51P(B)=0.51 and P(A\cap B)=0.468P(A∩B)=0.468, find the value of P(B|A)P(B∣A), rounding to the nearest thousandth, if necessary.

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)