A small computing center has found that the number of jobs submitted per day to its computers has a distribution that is approximately mound-shaped and symmetric, with a mean of 78 jobs and a standard deviation of 6. Where do we expect approximately 95% of the distribution to fall? between 90 and 96 jobs per day between 72 and 84 jobs per day between 60 and 96 jobs per day between 66 and 90 jobs per day

The answer is "between 60 and 96 jobs per day".

Step-by-step explanation:

In this solution, there is a mound-sized and symmetrical distribution for the number of works submitted to your computer per day with mean=78, and standard deviation=6.

Therefore a distribution of 95% decreases between the average 3* standard deviation

Therefore,

The 95% distribution falls in between 60 and 96 jobs per day.

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of