Can someone please solve these?

Step-by-step explanation:

h = -6 +20t + 4

I will use calculus,  maybe that's not how you're supposed to do this

-12t +20 =0

12t = 20

t = 20 /12

t = 1

t = 1

there will be a max at  1.6666666666  seconds

-6*  + 20 * 1.6666666666  +4

= 16.666666666666 + 33.333333333333 + 4

= - 16 + 33 + 4

= 20  feet max height ( not too high,  for a rocket)

time of flight:

0 = -6 +20t + 4

use quadratic formula to find t

-20 +- sqrt [ - 4*(-6)*4 ] / 2*(-6)

-20 +- sqrt [400 + 96 ] / -12

-20 +- sqrt [496 ] / -12

-20 +- 22.27105 / -12

try the negative option 1st

-42.27105 / -12

3.522 seconds.     time of flight

when will the rocket be at 12' ? :

12 = -6 +20t + 4

0 = -6 +20t -8

use quadratic formula again to find t

-20 +- sqrt [ - 4*(-6)*(-8) ] / 2*(-6)

-20 +- sqrt [ 400 - 192 ] / -12

-20 +- sqrt [208 ] / -12

-20 - 14.4222 / -12

-34.4222 / -12

2.8685 seconds ( on the way down)

and

-20 + 14.4222 / -12

-5.578 / - 12

0.4648  seconds ( on the way up )

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: