One friend’s phone willindependently drop calls with 20% probability. Your other friend’s phone will independentlydrop calls with 30% probability. Say you need to make 6 phone calls, so you randomly chooseone of the two phones and you will use thatsamephone to make all your calls (but you don’tknow which has a 20% versus 30% chance of dropping calls). Of the first 3 (out of 6) callsyou make, one of them is dropped. What is the conditional expected number of dropped callsin the 6 total calls you make (conditioned on having already had

no not all of them.

step-by-step explanation:

some of them have a square base.

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

think about it deeply and passionately about this property

i am sorry

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!