IM USING 20 POINTS FOR THIS PLS HELP AND SHOW WORK

the object is in the air on the time interval (0.24 sec, 6.51 sec)

Step-by-step explanation:

The object is 'in the air' for all t such that h> 0.  We need to find the roots of h = -16t^2 + 108t - 25 = 0.  From the graph we see that both t values are positive.  Once we find them, we subtract the smaller t from the larger t, which results in the length of time the object is in the air.

Use the quadratic formula to find the roots of h(t).  The coefficients of t are {-16, 108, -25}, and so the discriminant b^2 - 4ac is

108² - 4(-16)(-25) = 11664 - 1600 = 10064, whose square root is 100.32.

Then the quadratic formula x = (-b ± √[b² - 4ac)/(2a) becomes

      -108 ± 100.32       108 ± 100.32

t = = = 3.375 ± 3.135

             2(-16)                      32

or t = 6.51 or t = 0.24  (both times expressed in seconds).

So, again, the object is in the air on the time interval (0.24 sec, 6.51 sec)

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^