The sides of an isosceles triangle have lengths of 10, 10, and 4. Find the measures of the base angles.

The base angles measure 78.46 degrees to the nearest hundredth.

Step-by-step explanation:

Applying the Cosine Rule:

10^2 = 10^2 + 4^2 - 2.4.10cosX     where X is a base angle.

cos X = (100 - 100 - 16)/ (-80)

cos X = -16/-80

cos X = 0.2

X = 78.463 degrees

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation: