Why can V-1 be written as an integer, but V1 cannot? (please look at photo)​

This is because the cube root of -1 gives a real number while the square root gives a complex number root value which we cannot write as an integer

Step-by-step explanation:

This is because, -1 raised to the power of 3 will give -1

However, -1 does not have any real root

Take for example, the square of -1 is 1

Hence the square root of -1 is not a real number which we can write as integer but a complex number which is not real

step-by-step explanation:

80 the answer is 80

step-by-step explanation: