Plases help if you can thank you A line segment has an endpoints at (-3, 7) and (17, -3). What is the location of the point that divides the segment in a ratio of 2:8?
Select one:

(15, -2)

(9, 1)

(1, 5)

(-1, 6)

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

answer: i think it's a

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

$6.42

step-by-step explanation: