The function y=-162x2v0x models the height of a golf ball in feet x seconds after a player hits it. In the equation of the function, v0 is in the initial velocity of the ball in feet per second. The ball returns to the ground 3 second after it is hit. What is the value of v0

2? if not the correct answer you might need to provide more information

step-by-step explanation:

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^