What is the slope of a line perpendicular to line 6x + 3y = 15

Step-by-step explanation:

Given line is 6x+3y=15

Slope of the given line (m)=-x/y

=-6/3

=-2

let slope of the line perpendicular to the given line be m'.

Condition of perpendicularity,

m×m'=-1

-2×m'=-1

m'=-1/-2

m'=1/2

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz