H(x)=2x^2−11x+15 Use the drop-down menus to factor the expression and find the zeros of h(x).

h(x)=(2x − 5)(x − 3)

The zeros of h are 3 and 5/2

Step-by-step explanation:

the guy that asked is right :)

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

i think it might be a but you might want a second opinion