This is due in a few hours and I’m having some troubles. Supposed to simplify the left side of the each equation so that it’s the same as the right side. ( I’m supposed to show work )

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .

Find the value of x. give reasons to justify your solutions! c ∈ ae

The median for the given set of six ordered data values is 29.5 9 12 25 __ 41 48 what is the missing value?