Define a relation Q on the set Rx R as follows. For all ordered pairs (w, x) and (y, z) in RxR, (w, x) Q (y, z) = x= z. (a) Prove that is an equivalence relation. To prove that is an equivalence relation, it is necessary to show that is reflexive, symmetric, and transitive. Proof that Q is an equivalence relation: (1) Proof that Q is reflexive: Construct a proof by selecting sentences from the following scrambled list and putting them in the correct order.
a. By the reflexive property of equality, x = x
b. By definition of Q, (w, x) = (w, x).
c. By the symmetric property of equality, w = w.
d. By the reflexive property of equality, w = w.
e. By the symmetric property of equality, x = x.

f(x) = y

f(-3) = -5

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺