What is an equation of the line that passes through the points (6, -7) and (-6,3)?

y=-5/6x-2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-7))/(-6-6)

m=(3+7)/-12

m=10/-12

simplify

m=-5/6

y-y1=m(x-x1)

y-(-7)=-5/6(x-6)

y+7=-5/6x+30/6

y+7=-5/6x+5

y=-5/6x+5-7

y=-5/6x-2

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

a is the right answer