The perimeter of a rectangle is 72 cm. The length is 3 more than twice the width What are the dimensions?

Given :-

Find :-

Using Formula

Let,

According to question,

==> perimeter of Rectangle = 72

==> 2(x+y) = 72

==> x + y = 72/2

==> x + y = 36_________________(1)

Again,

==> x = 2y + 3

==> x - 2y = 3__________________(2)

Subtract equ(1) & equ(2)

==> y + 2y = 36 - 3

==> 3y = 33

==> y = 33/3

==> y = 11

keep in equ(1)

==> x - 2×11 = 3

==> x = 3 + 22

==> x = 25

sine

step-by-step explanation: