A ball is thrown into the air with an upward velocity of 12 meters per second. Its height h in meters after t seconds is given by the function h=-16 + 12t + 5. How long will it take the ball to reach its maximum height? What is the ball's maximum height? What is the range of the function? look at the picture as well ​

-16(5/8)^ 2 + 20(5/8) + 6  =   12.25  ft

Step-by-step explanation:

h = -16t^ 2 + 20t + 6  the ball will hit the ground when h  = 0

0 = -16t^2  + 20t   + 6      factor

0  = ( -8t  -  2 )  ( 2t  - 3)     set each  factor to 0                        

-8t  -  2  =  0   and   2t  - 3   = 0

-8t   = 2             2t   =   3

t  = -2/8  = - 1/4  sec        t  = 3/2 sec  = 1.5 sec

Max hit will be reached at [ -b / 2a ]    sec    =  -20 / [ 2(-16)]  =  20/32  =  5/8 sec

 -16(5/8)^ 2 + 20(5/8) + 6  =   12.25  ft

17

step-by-step explanation:

51/3=17

thus 17 is your answer.