In a storeroom, there are 30 blue balls,48 green balls, some red balls and some white balls. there are 3 times as many green balls as red balls and 5 times as many blue balls as white balls. (a) How many balls are there altogether?
(b) How many balls are left in the room if 7/10 (fraction) of the balls are taken away?
pls help me answer both

7/30

Step-by-step explanation:

We first have 7 blue and 3 red out of 10, so P(1st ball is red) = 3/10

Now, we have pulled a red ball out of the bag, leaving us with 7 blue and 2 red out of 9 total balls.Then P(2nd ball is blue) = 7/9.  Put this together, P(1st red AND 2nd blue) = 3/10⋅7/9 =7/30

i think the answer is b.

step-by-step explanation:

not 100% sure though.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!