In HIJ the measure of J equals 90° the measure of age equals 84° in IJ equals 2.9 feet find the length of JH to the nearest 10th of a foot

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

cheater

step-by-step explanation:

answer: answer is b.

[m < b = 120º]

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