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Mathematics, 21.05.2021 07:40 briannaalvarado256

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sec^2 \theta +cosec^2\theta = (tan \theta +cot \theta )^2
\frac{1-tan^2\theta}{1+tan^2\theta} =(cos +sin \theta)(cos \theta -sin \theta)
\frac{sin \theta}{1-cot \theta}+\frac{cos \theta}{1-tan \theta} =cos \theta +sin \theta

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