The value of an investment property after t years can be found using the formula V =C (1 + r)^2, where V is the current value of the property, C is the original investment,
and r is the annual rate of appreciation.
a. Solve the formula for r.
b. Lew bought a condo 20 years ago for $50,000, and the current value of the condo is $175,000. Assuming the same
rate each year, what has the annual rate of appreciation been? Round your answer to the nearest half a percent.

0.871

Step-by-step explanation:

a. Solve the formula for r.

V = C (1 + r)²

dividing both sides by C, we have

V/C = (1 + r)²

(1 + r)² = V/C

taking square root of both sides, we have

√(1 + r)² = √(V/C)

1 + r = √(V/C)

r = √(V/C) - 1

b. Lew bought a condo 20 years ago for $50,000, and the current value of the condo is $175,000. Assuming the same

rate each year, what has the annual rate of appreciation been? Round your answer to the nearest half a percent.

Since r  = √(V/C) - 1 and V = $ 175,000 and C = $ 50,000

Substituting the values of the variables into the equation for r, we have

r  = √($ 175,000/$ 50,000) - 1

r  = √3.5 - 1

r = 1.871 - 1

r = 0.8708

r ≅ 0.871

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

lol we need to see what the question is asking about

step-by-step explanation: