Which statement correctly uses limits to determine a vertical asymptote of g (x) = StartFraction negative 7 (x minus 5) squared (x + 6) Over (x minus 5) (x + 5) EndFraction There is a vertical asymptote at x = 5, because Limit of g (x) as x approaches 5 minus = infinity and limit of g (x) as x approaches 5 plus = negative infinity There is a vertical asymptote at x = 5, because Limit of g (x) as x approaches 5 minus = negative infinity and limit of g (x) as x approaches 5 plus = infinity There is a vertical asymptote at x = –5, because There is a vertical asymptote at x = –5, because