There are 9 red, 5 yellow, and 7 green jellybeans in a jar. Without replacement what is the probability of choosing a green jellybean followed by a red jellybean?

3/14 chance first draw

Step-by-step explanation:

There are 14 jellybeans in all, you won’t be replacing so the probability will change with each draw.

Probability the 1st draw is red = 3/14.

Probability the 2nd draw is red = (3–1)/(14–1) = 2/13.

Probability the 3rd draw is red = (2–1)/(13–1) = 1/12.

3/14 x 2/13 x 1/12 = 6/2184 = 1/364 is approximately 0.27%, pretty rare.

there is no picture in order for this question to be answered

if e is the midpoint of bd, then bd is 14.

step-by-step explanation: