. If sin (A + B) = 1 and tan (A - B) = 1/v3, find the value of:
i) tan A+ tan B
ii) sec A- cosec B
​

If  sin (A + B) = 1

and tan (A - B) = 1/√3

value of:

We know that,

So,

A + B + A - B = 90 + 30

(A + A) + (B - B) = 120

2A = 120

A = 120/2

By putting value of A in 2

A - B = 30

60 - B = 30

-B = 30 - 60

-B = -30

tan 60 + tan 30

We know that

√3 + 1/√3

√3 × √3 + 1/√3

3 + 1/√3

sec A- cosec B

sec 60 - cosec 30

We know that

2 - 2 =

tan A+ tan B=4/√3

sec A- cosec B=0

you should talk someone who owns the website about it. you did not deserve to have all that hard work and time taken away. id watch videos of little puppies to cool you down, and maybe some nacho cheese doritos.