A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and il will choose the other foods on the next trial with equal probabilities of 25%. If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

As we know that,

The matrix is a Markov chain

Let

The initial state vector be

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

∴ we get

Now,

∴ we get

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

idk bring the function back   im not smart

step-by-step explanation:

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5