After standardizing a NaOH solution, you use it to titrate an HCl solution known to have a concentration of 0.205 M. You perform five titrations and obtain the following results: 0.213, 0.204, 0.208, 0.200, and 0.198 M. a) What is the mean?
b) What is the standard deviation of mean?

The right answer is:

(a) 0.205

(b) 0.005425

Step-by-step explanation:

The given data is:

0.213, 0.204, 0.208, 0.200, and 0.198

(a)

The mean will be:

=

=

=

=

or,

=

(b)

The standard deviation will be:

or,

345

step-by-step explanation:

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier