Consider the quadratic function defined by: f (x) = −3(x −1)(x + 6)
a. State the zeros of the function:
b. Express this function in standard form by expanding & simplifying.

Step-by-step explanation:

Given :-

And we need to find out the zeroes of the quadratic function and we need to express it in Standard form. T

Function :-

Therefore the zeroes are 1 and -6 .

Expressing in Standard form :-

The standard form of a quadratic equation is ,

And that of a quadratic function is ,

Simplifying the equation :-

Hence the Standard form of the equation is -3x² - 15x + 18 .

answer: i'm going in

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)