Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14

Step-by-step explanation:

The equation of the curve is

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is  

Then slope would accordingly be

= ∞

For, ,

Equation of tangent line, in the point slope form, would be

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.