V+2/v + 4/3v =11
How to solve this ?

0.189

4.525

Step-by-step explanation:

v/1 + 2/v + 4v/3 = 11

we can eliminate denominators if we distribute 3v to each term:

3v(v/1 + 2/v + 4v/3) = 3v(11)

3v² + 6 + 4v² = 33v

7v² - 33v + 6 = 0

factor this trinomial:

there are no factors of 6 that would add to -33 so we can use the quadratic formula to solve:  (-b ± √b²-4ac) / 2a

a = 7

b = -33

c = 6

[33 ± √(-33)² - 4(7)(6)] / 2(7)

(33 ± √1089 - 168) / 14

(33 ± √921) / 14

(33 ± 30.35) / 14

(33+30.35) / 14 =  4.525

(33-30.35) / 14 =  0.189

explanation:

step-by-step explanation:

step-by-step explanation: