A figure is located at (2.0), (2, -2), and (6.0) on a coordinate plane. What kind of 3-D shape would be created if the figure was rotated around the x-axis ? Provide an explanation and proof of your answer to receive full credit. Include the dimensions of the 3-D shape in your explanation.
Source

i think the answer is b x = 1, y = 35/2

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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26 + 8 = 2*13 + 2*4 = 2*(13+4) = 2*(17)