Question 11: A diesel train traveled to Johannesburg and back. The trip there took 6 hours and
the trip back took 9 hours. It averaged 23 miles per hour faster on the trip there
than on the return trip. Find the diesel train's average speed on the outbound (first
part traveling to Johannesburg) trip.

69 miles per hour

Step-by-step explanation:

Given

Trip to:

--- time

Trip back

Required

Determine the average speed to Johannesburg

Average speed is calculated as:

Make distance the subject

Since distance is constant, then:

This gives:

Open bracket

Collect like terms

Solve for s2

Recall that:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.